470,809 views
15 votes
15 votes
PLEASE PLEASE HELP ME

PLEASE PLEASE HELP ME-example-1
User Sngreco
by
3.0k points

2 Answers

15 votes
15 votes

Go through second method

Area of one traingle'-

  • 1/2(1.5)4
  • 2(1.5)
  • 3cm²

Area of two triangles=6cm²

Area of rectangle

  • (15-4)(3)
  • 11(3)
  • 33cm²

Total:-

  • 33+6
  • 39cm²

PLEASE PLEASE HELP ME-example-1
User Bousof
by
2.6k points
10 votes
10 votes

Answer:

Method 1

Find the area of the rectangle, 45 cm². Subtract the area of the cut-out triangle from the rectangle, 45 - 6 = 39 cm²

Method 2

Separate the ribbon into two triangles and a rectangle.

33 + 3 + 3 = 39 cm²

Explanation:

Formulae

  • Area of a rectangle = width × length
  • Area of a triangle = 1/2 × base × height

Method 1

Area of the rectangle:

= 3 × 15

= 45 cm²

Area of the cut-out triangle:

= 1/2 × 3 × 4

= 6 cm²

Find the area of the rectangle, 45 cm². Subtract the area of the cut-out triangle from the rectangle, 45 - 6 = 39 cm²

Method 2

Area of the rectangle:

= 3 × (15 - 4)

= 3 × 11

= 33 cm²

Area of one triangle:

= 1/2 × (3 ÷ 2) × 4

= 3 cm²

Separate the ribbon into two triangles and a rectangle.

33 + 3 + 3 = 39 cm²

User Dantheta
by
2.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.