Question

the figure above is made up of a square and an isosceles right triangle. if EC=22, find the perimeter of BAFEC

Answer 1

88+22√2

Explanation:

By seeing that EC is 22, we are able to see 4 of the 5 sides are the same. Then, we need to find the hypotenuse of the remaining side (22√2)

Then we can add (22 × 4) and (22√2) to get the answer, 88+22√2

Answer 2

Perimeter: 119.11 units length

Explanation:

Assuming that EC is the length of one side of the square and one of the legs (l) of the isosceles right triangle, then the hypotenuse (h) of the right triangle is:

h² = 2*l²

h = √(2*22²)

h = 22√2 units length

The perimeter of the figure is the addition of 3 sides of the square, one leg of the triangle and the hypotenuse of the triangle, that is: 4*22 + 22√2 = 22*(4 + √2) ≈ 119.11 units length