Question

or a metal pipe used to pump tomato paste, the overall heat- transfer coefficient based on internal area is 2 W/(m2 K). The inside diameter of the pipe is 5 cm. The pipe is 2 cm thick. The thermal conductivity of the metal is 20 W/(m K). Calculate the outer convective heat-transfer coefficient. The inside convective heat-transfer coefficient is 5 W/(m2 K).

Answer 1

To calculate the outer convective heat-transfer coefficient, you can use the equation 1/h_outer = 1/h_inner + d/k + ln(r_outer/r_inner) / 2πk.

Step-by-step explanation:

To calculate the outer convective heat-transfer coefficient, we can use the equation:

1/h_outer = 1/h_inner + d/k + ln(r_outer/r_inner) / 2πk

Where:

• h_outer is the outer convective heat-transfer coefficient.
• h_inner is the inner convective heat-transfer coefficient.
• d is the thickness of the pipe.
• k is the thermal conductivity of the metal.
• r_outer is the outer radius of the pipe (r_outer = r_inner + d).
• r_inner is the inner radius of the pipe (r_inner = diameter/2).

Using the given values:

• h_inner = 5 W/(m2 K)
• d = 2 cm = 0.02 m
• k = 20 W/(m K)
• r_inner = 5 cm/2 = 0.025 m

we can plug these values into the equation and solve for h_outer:

1/h_outer = 1/5 + 0.02/20 + ln((0.025 + 0.02)/(0.025)) / 2π * 20

1/h_outer ≈ 0.2 + 0.001 + 0.00088

1/h_outer ≈ 0.20188

h_outer ≈ 4.95 W/(m2 K)

Answer 2

Answer: ok the best one would be letter s because it goes

Step-by-step explanation:

467,,mm tubing should do