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Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square?

Four circles, each with a radius of 2 inches, are removed from a square. What is the-example-1
User Phyliss
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2 Answers

4 votes

Answer:(64-16pi)in.^2

Explanation:

I got it right on e 2020

User Jloubert
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0 votes

Given:

Given that the radius of the circle is 2 inches.

We need to determine the area of the remaining square.

Area of a square:

Given that each circle has a radius of 2 inches.

Then, the diameter of each circle is 4 inches.

Hence, the side length of the square is 2 × 4 = 8 inches.

The area of the square is given by


A=s^2


A=8^2


A=64 \ in^2

Thus, the area of the square is 64 square inches.

Area of the four circles:

The area of one circle is given by


A=\pi r^2

Substituting r = 2, we have;


A=4 \pi

Thus, the area of one circle is 4π in²

The area of 4 circles is 4 × 4π =16π in²

Hence, the area of the 4 circles is 16π in²

Area of the remaining square:

The area of the remaining square is given by

Area = Area of the square - Area of four circles.

Substituting the values, we get;


Area = 64-16 \pi

Thus, the area of the remaining square is (64 - 16π) in²

Hence, Option c is the correct answer.

User Tiago Peres
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