Question

50 grams of water (c=4.186 J/gC) starting at 20 degrees C cools and turns to ice at 0 degrees C. How much heat will be released? *

Answer 1

4,186 Joules of Heat Released

Step-by-step explanation:

When calculating Specific Heat, it is good to remember two formulas:

`Q = Cp * m* Delta T`

And

`Cp = (Q)/(m * Delta T)`

For this problem, we are using the first eqution to find the missing variable Q or the amount of joules released. The work would look like this:

`Q = Cp * m * DeltaT\\Q = 4.186 J/g*C * 50g * (20-0)\\Q= 4.186 J/g*C * 50g * 20\\Q = 4,186 J\\`

Hope this Helps!