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If P=x²-yz , Q=y²-x² ,R=z²-xy, Then find PQR

User Tomvo
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1 Answer

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PQR=( {x}^(2) - yz)( {y}^(2) - {x}^(2) )( {z}^(2) - xy) = \\ = {x}^(2) {y}^(2) {z}^(2) - {x}^(3) {y}^(3) - {x}^(4) {z}^(2) + {x}^(5) y - {y}^(3) {z}^(3) + \\ + x {y}^(4) z + xy {z}^(3) - {x}^(2) {y}^(2) z

I don't know if it was necessary to open the brackets, but I think you can write it like this:


PQR=( {x}^(2) - yz)( {y}^(2) - {x}^(2) )( {z}^(2) - xy) \\

User Star Brilliant
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