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5 votes
Answered
3x2 – 41x = -110
use quadratic formula

User Bergyman
by
8.4k points

1 Answer

5 votes

Answer: x=10 and x= 3.66667

Explanation:

you would need to at 110 to both side to get c before you can solve the quadratic formula, once you have done that you should get 3x2-41x+110=0 than you can now put it in to the formula(-b
\frac{-b(+-)\sqrt{b^(2-4ac) } }{2a}) which will now be
\frac{-(-41)(+-)\sqrt{41^(2-4(3)(110)) } }{2(3)} than solve
(41(+-)√(1681-1320) )/(6) now combined to get
(41(+-)√(361) )/(6) the discriminant
b^(2)-4sc > 0 so there are two real roots which are,
x= (41(+-) 19)/(6) simplify the radicals, x
(60)/(6)= and x =
(22 )/(6) that will turn into x = 10 and x= 3.66667

User Daniloxvalle
by
8.3k points

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