Question

Answered
3x2 – 41x = -110
use quadratic formula

Answer 1

Answer: x=10 and x= 3.66667

Explanation:

you would need to at 110 to both side to get c before you can solve the quadratic formula, once you have done that you should get 3x2-41x+110=0 than you can now put it in to the formula(-b
`\frac{-b(+-)\sqrt{b^(2-4ac) } }{2a}`) which will now be
`\frac{-(-41)(+-)\sqrt{41^(2-4(3)(110)) } }{2(3)}` than solve
`(41(+-)√(1681-1320) )/(6)` now combined to get
`(41(+-)√(361) )/(6)` the discriminant
`b^(2)`-4sc > 0 so there are two real roots which are,
`x= (41(+-) 19)/(6)` simplify the radicals, x
`(60)/(6)`= and x =
`(22 )/(6)` that will turn into x = 10 and x= 3.66667