194k views
0 votes
Punkt p (1;2k+1) należy do wykresu funkcji f(x)=-4x2+7. Oblicz k

1 Answer

4 votes

Answer:

k = 1

Explanation:

English Translation

Find k if the point P (-1, 2k + 1) belongs to the graph of the function f (x) = - 4x^2 + 7.

The function is given as

y = f(x) = -4x² + 7

and point (-1, 2k+1) lies on the graph.

This point means that, at x = -1, y = 2k+1

y = -4x² + 7

Substituting the values in

2k + 1 = -4(-1)² + 7

2k + 1 = -4 + 7 = 3

2k = 3 - 1

2k = 2

k = 1

Hence, the point (-1, 2k+1) is (-1, 3)

To check,

y = -4x² + 7

3 = -4(-1)² + 7

3 = -4 + 7

3 = 3

So, this is truly correct.

Hope this Helps!!!

User Nino Van Hooff
by
9.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.