Answer:
Stabilizer with area = 14 cm².
Explanation:
Area of the wing = 101.25 cm²
Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.
1/6 of the area of wing =
![(1)/(6) * 101.25 = 16.875](https://img.qammunity.org/2021/formulas/mathematics/high-school/b8lfizwai1ptyuhtdy4kdxtqlvzxovglw0.png)
1/8 of the area of wing =
![(1)/(8) * 101.25 = 12.656](https://img.qammunity.org/2021/formulas/mathematics/high-school/zsag0iq7irqai85zsyhsqivi5327bc9ukk.png)
This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²
Therefore, area of a good stabilizer design from the given options would be 14 cm²