Answer: The smallest sample size would be 392.
Step-by-step explanation:
Since we have given that
Standard deviation = 12 minutes
Mean = 68 minutes
Margin of error =
![\pm 1](https://img.qammunity.org/2021/formulas/mathematics/college/vgcyk5dfpverc8caavopjy4sav796rc27s.png)
At 90% confidence interval, z = 1.65
So, the smallest sample size that we should consider would be
![n=((z* \sigma)/(ME))^2\\\\n=((1.65* 12)/(1))^2\\\\n=(19.8)^2\\\\n=392.04\\\\n=392](https://img.qammunity.org/2021/formulas/sat/middle-school/a95dcgcrl29w81k283waknd4gpory1gktp.png)
Hence, the smallest sample size would be 392.