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A machine part has the shape of a solid uniform sphere of mass 250 g and a diameter of 4.30 cm. It is spinning about a frictionless axle through its center, but at one point on its equator it is scraping against metal, resulting in a friction force of 0.0200 N at that point.

PART (A):

Find its angular acceleration. Let the direction the sphere is spinning be the positive sense of rotation.

PART (B):
How long will it take to decrease its rotational speed by 21.0 Rad/s?


****NOTE: For part (A), I've tried solving using a similer question, and I got Angular Accelration = 6.59 Rad/s^2 which is wrong, according to Mastering Physics. For Part (B) I got 6.5 seconds, which is also wrong. I don't understand what I'm doing wrong since I followed the exact same method used in the same question posted on chegg. ****

User EGeuens
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1 Answer

4 votes

Answer:
\alpha =9.302\ rad/s^2

Step-by-step explanation:

Given

mass of sphere
m=250\ gm

diameter of sphere
d=4.30\ cm

radius
r=(4.30)/(2)\ cm


f=0.0200\ N

friction will provide resisting torque so


f* r=I* \alpha

where
I=\text{moment of Inertia}


f=\text{friction force}


\alpha =\text{angular acceleration}


I=(2)/(5)mr^2


0.02* r=(2)/(5)mr^2* \alpha


\alpha =(5)/(2r)* f


\alpha =(5)/(2)* (2)/(4.3* 10^(-2))* 0.02


\alpha =9.302\ rad/s^2

(b)time taken to decrease its rotational speed by
21\ rad/s


t=(\Delta \omega )/(\alpha )


t=(21)/(9.302)


t=2.25\ s

User Sney
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4.9k points