Question

The Irregular figure can be broken into a triangle and a rectangle as shown with the dashed line.

Answer 1

The answers your ACTAULLY looking for is

Explanation:

1. 2 2/3

2. 4

3. 6 2/3

4. 10 2/3

( I know these answers cause I got them wrong and told me the correct answers)

Answer 2

Given:

Given that the irregular figure is broken into a triangle and a rectangle.

We need to determine the length b, the area of the triangle , the area of the rectangle and the area of the irregular figure.

Length of b:

The length of b , the base of the triangle is given by

`b=5-(2(1)/(3))`

Simplifying, we get;

`b=5-(7)/(3)`

`b=(8)/(3) \ ft`

Thus, the length of the base of the triangle is
`(8)/(3) \ ft`

Area of the triangle:

The area of the triangle can be determined using the formula,

`A=(1)/(2)bh`

Substituting
`b=(8)/(3) \ ft` and
`h=3 \ ft`, we get;

`A=(1)/(2)((8)/(3))(3)`

`A=4 \ ft^2`

Thus, the area of the triangle is 4 square feet.

Area of the rectangle:

The area of the rectangle can be determined using the formula,

`A=lw`

where l = 5 ft,
`w=1 (1)/(3)=(4)/(3) \ ft`, we get;

`A=5 * (4)/(3)`

`A=(20)/(3) \ ft^2`

Thus, the area of the rectangle is
`(20)/(3) \ ft^2`

Area of the irregular figure:

The area of the irregular figure can be determined by adding the area of the triangle and the area of the rectangle.

Thus, we have;

Area = Area of the triangle + Area of the rectangle

Substituting the values, we have;

`Area = 4+(20)/(3)`

`Area = 10.667 \ ft^2`

Thus, the area of the irregular figure is 10.667 square feet.