Question

An 886 mL sample of Neon gas is at 752 torr and 299 K. What will be the new volume if, with the pressure and amount of gas held constant the temperature is decreased to 253 K?

Answer 1

749.69 ml is the new volume if, with the pressure and amount of gas held constant the temperature is decreased to 253 K.

Step-by-step explanation:

Data given:

Initial volume of the neon gas V1 = 886 ml

initial pressure of the neon gas P1 = 752 torr or

initial temperature of the neon gas T1 = 299 K

Final volume =?

pressure constant so final pressure = initial pressure hence P2 = P1

fInal temperature of the neon gas T2 = 253 K

applying the Gay Lussac equation

`(P1V1)/(T1)` =
`(P2V2)/(T2)`

Pressure can be removed from the equation as it is constant, so we apply Charles' Law equation:

`(V1)/(T1)` =
`(V2)/(T2)`

rearranging the above equation to know final volume:

V2=
`(V1T2)/(T1)`

V2 =
`(886 X253 )/(299)`

V2 = 749.69 ml

final volume is 749.69 ml