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Expected value is

a. ​(Probability of state A+Value in state A) (Probability of state B+Value in state B)
b. ​(Probability of state A*Value in state A)-(Probability of state B*Value in state B)
c. ​(Probability of state A*Value in state A)+(Probability of state B*Value in state B)
d. ​(Probability of state A-Value in state A) (Probability of state B-Value in state B)

1 Answer

5 votes

Answer:

(C). ​(Probability of state A*Value in state A)+(Probability of state B*Value in state B)

Explanation:

The expected value of a probability distribution, E(X) is defined as:


E(x)=\sum_(i=1) ^(k) x_(i) \cdot P(x_(i))\\$Where x=An Outcome\\P(x)=Probability of that Outcome

Given Outcome A and B, the Expected Value therefore is:

Expected Value = ​(Probability of state A*Value in state A)+(Probability of state B*Value in state B)

User Greg Zimmers
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