Question

The metal zinc has free electron concentration per unit volume, nv, of 1.31029/m3 and an electron mobility me of 8104 m2/V.s. The charge carried by an electron, e, is 1.61019 coulomb. Based on this information, what is the electrical conductivity of zinc? Handbooks list the measured resistivity of zinc as 5.9 mU.cm. Is this consistent with your calculation? (Watch the units.)

Answer 1

1.7*10^{12}Ucm^-1

Step-by-step explanation:

The answer to this question is obtained by using the following formula:

`\sigma=nq\mu_e`

sigma: conductivity

q: charge of the electron = 1.61019*10^{-19}C

mu_e: electron mobility = 8104 m^2/Vs

n: free electron concentration = 1.31029/m^3

By replacing you get:

`\sigma=(1.31*10^(29)/m^3)(1.61*10^(-19)C)(8104 m2/Vs)=1.709*10^(14)\Omega^(-1)m^(-1) \\\\1.709*10^(14)\Omega^(-1) (1*10^(2)cm})^(-1)=1.7*10^(12)\Omega^(-1)cm^(-1)`

the result obained is not 5.9mU.cm. This is because temperature effects has not taken into account.