Answer:
![p_r=(h)/(\lambda)](https://img.qammunity.org/2021/formulas/physics/high-school/y5nlzk1bjxigj2e3rnls685vpmc3a8tohd.png)
Step-by-step explanation:
To find the momentum of the recoiling particle you can use the momentum formula for a photon:
![p=(h)/(\lambda)](https://img.qammunity.org/2021/formulas/physics/high-school/vrg6zzmeq580ylc0f828zlhkuq1azbbzha.png)
before the decay the momentum is zero. Hence, after the decay the momentum of the photon plus the momentum of the recoiling particle must be zero:
![p_a=p_b\\\\(h)/(\lambda)-(m)/(2)v=0\\\\p_r=(m)/(2)v=(h)/(\lambda)](https://img.qammunity.org/2021/formulas/physics/high-school/8y0nakg764qsbsazopiu5ymb29gqbgpmjd.png)
where pr is the momentum of the recoiling particle.