Question

"two stations communicate via a 1-mbps satellite link with a propagation delay of 279 ms. the satellite serves merely to transmit data received from on station to another, with negligible switching delay. using hdlc frames of 1024 bits with 3-bit sequence numbers, what is the maximum possible data throughput, that is, what is the amount of data bits transferred using hdlc frame per second?"

Answer 1

The answer is "
`\bold{11964.9 * 10^3 kbps}`"

Step-by-step explanation:

The

`t_(pd) = 279 \ ms`

`t_(single) = \frac{Bits \ HDLC} {Link \ rate}\\`

`t_(single) = (1024 )/(10^6) \ ms\\`

Transmit station can controls at most 7 frames in 3 bit sequence and without act total time to transmit.

Total time (t) = time for first frame + 2(frame delays)

`t=(1024)/(10^6)+ 279+279\\\\t= 0.571 m`

during the time t frame sent = 7 So, data on each frame is

frame = frame size - ( flag + address+control+fcs bits +flag hits)

frame = 1024 -(8+8+8+16+8)

frame= 976 bits frame

through put =
`(7 * 976)/(0.571 * 10^(-3))\\`

through put =
`(6832 * 1000)/(0.571)` =
`11964.9 * 10^3` kbps