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In a cyclic quadrilateral ABRS, if AR=BS, prove that AS=RB and AB is parallel to SR​
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In a cyclic quadrilateral ABRS, if AR=BS, prove that AS=RB and AB is parallel to SR​

User Raky
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arc. BRS=arc. ASR(being AR=BS)
arc. BRS-arc. SR=arcade-arc. SR(removing SR in both side)
arc. AS=arc. BR
AS=BR(arc. AS=arc. BR)
AB//SR(same reason)

User Sydwell
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