In a cyclic quadrilateral ABRS, if AR=BS, prove that AS=RB and AB is parallel to SR

asked Nov 22, 2023 112k views

5 votes

by Raky

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1 vote

arc. BRS=arc. ASR(being AR=BS)
arc. BRS-arc. SR=arcade-arc. SR(removing SR in both side)
arc. AS=arc. BR
AS=BR(arc. AS=arc. BR)
AB//SR(same reason)

Sydwell answered Nov 28, 2023

3.4k points

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