Question

Please consider the following gas phase reaction and its experimentally determined rate law expression. If the concentration of A is tripled and the concentration of B is doubled, the reaction rate would be increased by a factor of:_________.

A + B → C rate = k[A]^2 [B]
A) 6
B) 9
C) 12
D) 18
E) 36

Answer 1

D) 18

Step-by-step explanation:

Hello,

In this case, by considering the given rate law:

`r=k[A]^2[B]`

We also take into account that the concentration of A is tripled and the concentration of B is doubled, therefore, we have:

`r=k[3*A]^2[2*B]`

Which results in an increasing factor of:

`3^2*2=9*2=18`

By considering only the tripling and the doubling, thus, the answer is D) 18.

Regards.