Question

How to find the product of (3y^2+ 2y + 2)(3y^2- 4y - 5)

Answer 1

= 9y^4 -6y^3 -17y^2 -18y -10

Explanation:

(3y^2 + 2y + 2) x (3y^2 – 4y – 5)

9y^4 - 12y^3 - 15y^2 + 6y^3 -8y^2 -10y +6y^2 -8y -10

= 9y^4 -6y^3 -17y^2 -18y -10