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If 211 mL of water is added to 5.00 mL of 3.24 M NaCl solution,

what is the concentration of the dilute solution?

1 Answer

5 votes

Answer:

0.075M

Step-by-step explanation:

-The concentration of a solution is defined as the mass of the solute divided by the volume of the solution:


Concentration=(Mass \ Solute)/(Volume \ of \ Solution)

-We the solve the molarity problem as follows:


M_1V_1=M_2V_2\\\\V_2=V_1+211=211+5=216mL\\\\\therefore M_2=(M_1V_1)/(V_2)\\\\=(3.24* 5)/(216)\\\\\\=0.075\ M

Hence, the concentration of the dilute solution is 0.075M

User Richard Whitehead
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