Question

If 211 mL of water is added to 5.00 mL of 3.24 M NaCl solution,

what is the concentration of the dilute solution?

Answer 1

0.075M

Step-by-step explanation:

-The concentration of a solution is defined as the mass of the solute divided by the volume of the solution:

`Concentration=(Mass \ Solute)/(Volume \ of \ Solution)`

-We the solve the molarity problem as follows:

`M_1V_1=M_2V_2\\\\V_2=V_1+211=211+5=216mL\\\\\therefore M_2=(M_1V_1)/(V_2)\\\\=(3.24* 5)/(216)\\\\\\=0.075\ M`

Hence, the concentration of the dilute solution is 0.075M