To solve 49^3x = 343^2x+1, write each side of the equation in terms of base

Question

asked Dec 12, 2021 35.2k views

2 Answers

Susan Switzer · Answer 1 · 2021-12-13T15:08:37+0000

Answer:
(7)^(^6^x^)=(7)^(^6^x^+^3^)

Explanation:

49^3^x=343^2^x^+^1

(7^2)^(^3^x^)=(7^3)^(^2^x^+^1^)

(7)^(^6^x^)=(7)^(^6^x^+^3^)

Up to this points, is the equation in terms of base, from now on, I'm going to try to solve it.

Since we have the same base, exponents must be equal

$6x=6x+3\\6x-6x=3\\0=3$

Since we lost our variable, there's nothing to solve for. Therefore, this has no solution.