Question

To solve 49^3x = 343^2x+1, write each side of the equation in terms of base

Answer 1

Answer:
`(7)^(^6^x^)=(7)^(^6^x^+^3^)`

Explanation:

`49^3^x=343^2^x^+^1`

`(7^2)^(^3^x^)=(7^3)^(^2^x^+^1^)`

`(7)^(^6^x^)=(7)^(^6^x^+^3^)`

Up to this points, is the equation in terms of base, from now on, I'm going to try to solve it.

Since we have the same base, exponents must be equal

`6x=6x+3\\6x-6x=3\\0=3`

Since we lost our variable, there's nothing to solve for. Therefore, this has no solution.

Answer 2

first is 7, second is B, and 3rd is D no solution

Explanation:

got answers on edge