Find BC (round to the nearest hundredth)

Question

asked Sep 16, 2021 29.9k views

1 Answer

Knnhcn · Answer 1 · 2021-09-22T06:07:43+0000

Given:

In ΔABC, ∠C = 90°, ∠A = 50° and AB = 3 unit.

To find the value of BC.

Formula:

By Trigonometric Ratio we get,

$sin \ \theta=(opposite)/(Hypotenuse)$

Now,

With respect to θ = 50°, AB is the hypotenuse and AB is the opposite side.

So,

$sin \ 50^(\circ)=(BC)/(AB)$

$sin \ 50^(\circ)=(BC)/(3)$

$BC = 3 * sin 50^(\circ)$

BC = 2.298 = 2.3 (approx)

Hence,

The value of BC is 2.3 units.