119k views
5 votes
Help with properties of rhombus,rectangles and squares ​

Help with properties of rhombus,rectangles and squares ​-example-1
User Antwoine
by
4.0k points

2 Answers

4 votes

Answer:

a = 3

b = 4

c = 5

Explanation:

Rhombus has all sides equal

c = EH = sqrt(4² + 3²) = 5

Diagonals are Perpendicular bisectors of each other

b = 4

a = 3

User Derek Gogol
by
3.6k points
0 votes

Answer:

a = 3

b = 4

c = 5

Explanation:

This is a rhombus. A property of a rhombus is that their diagonals perpendicularly bisect each other. In other words, if the point in the center is A, then HA = MA and EA = OA. So: 3 = a and 4 = b.

Since angle HAO forms a right angle, we can use the Pythagorean Theorem to say that HA^2 + AO^2 = OH^2: 3^2 + 4^2 = 9 + 16 = 25.

OH^2 = 25

OH = 5

Hope this helps!

User Outlookrperson
by
4.1k points