Question

A 0.211 g sample of carbon dioxide, CO2, has a volume of 560 mL and a pressure of 429 mmHg whats the temperature of the gas in Kelvin

Answer 1

The temperature of the gas sample is 813 K.

Step-by-step explanation:

We have to use the ideal gas equation to find the temperature of the gas sample.

The ideal gas equation is PV = nRT

Pressure, P = 429 mm Hg = 0.56 atm

Volume, V = 560 mL = 0.56 L

R = gas constant = 0.08205 L atm mol⁻¹K⁻¹

Mass = 0.211 g

Molar mass of carbon di oxide = 44.01 g / mol

Moles, n =
`$(given mass)/(molar mass) = (0.211 g)/(44.01 g/mol)`

= 0.0047 mol

Now, we have to plugin the above values in the above equation, we will get the temperature as,

`$T= (PV)/(nR)`

T =
`$(0.56 * 0.56)/(0.08205 * 0.0047)`

= 813 K

So the temperature of the gas sample is 813 K.