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Find x on the triangle geometry please help

Find x on the triangle geometry please help-example-1
User Fabio Mora
by
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2 Answers

8 votes


\\ \rm\Rrightarrow cos\theta=(Base)/(Hypotenuse)


\\ \rm\Rrightarrow cos45=(7√(3))/(x)


\\ \rm\Rrightarrow (1)/(√(2))=(7√(3))/(x)


\\ \rm\Rrightarrow x=7√(3)√(2)


\\ \rm\Rrightarrow x=7√(6)

User Abuzze
by
7.9k points
13 votes

Answer:


\sf x=7√(6)

Explanation:

As the base angles of the triangle are the same, then the legs of the right triangle are also equal. Therefore, we can use Pythagoras' Theorem to calculate x.

Pythagoras' Theorem: a² + b² = c²

(where a and b are the legs, and c is the hypotenuse of the right triangle)

Given:

  • a = 7√3
  • b = 7√3
  • c = x

Substituting the given values into the formula:


\sf \implies (7√(3))^2+(7√(3))^2=x^2


\sf \implies147+147=x^2


\sf \implies x^2=294


\sf \implies x=√(294)


\sf \implies x=√(49 \cdot 6)


\sf \implies x=√(49)√(6)


\sf \implies x=7√(6)

User Krisp
by
7.8k points

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