Answer:
The calculated value t = 5.608 > 2.3988 at 0.1 level of significance with 53 degrees of freedom.
The null hypothesis is rejected at 0.1 level of significance
The company do not believes that there has been an INCREASE in the life expectancy of its D size batteries
Explanation:
Step(i):-
Given data the size of sample n=54
Given "D" size batteries produced by MNM Corporation have had a life expectancy of 85.8 hours
therefore mean of Population μ = 85.5 hours
Given a sample of 54 batteries showed an average life of 88.7 hours with a standard deviation of 3.8 hours
The mean of the sample x⁻ = 88.7 hours
The standard deviation of the sample (S) = 3.8 hours
Step(ii):-
Null hypothesis : H₀:μ > 85.5 hours
Alternative hypothesis: H₁:μ < 85.5 hours
Level of significance : ∝= 0.1
Degrees of freedom γ =n-1 = 54-1 =53
The test statistic
t = 5.608
The tabulated value t = 2.3988 at 0.1 level of significance with 53 degrees of freedom.
Conclusion:-
The calculated value t = 5.608 > 2.3988at 0.1 level of significance with 53 degrees of freedom.
The null hypothesis is rejected at 0.1 level of significance
The company do not believes that there has been an INCREASE in the life expectancy of its D size batteries