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What is the solution to X^2–64=0

User Gerd K
by
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1 Answer

4 votes

Answer:

x = 8, x = -8

Explanation:

Hello!

We can use the Difference of Squares Formula:
(a + b)(a - b) = a^2 - b^2

We need the two terms to be perfect squares for this formula to work, and subtraction has to be the operation. As you can see x² is a square of x, and 64 is the square of 8.

Solve:

  • x² - 64 = 0
  • (x + 8)(x - 8) = 0

Set each factor to zero. (Zero Product Property)

  • x + 8 = 0
  • x = -8

And

  • x - 8 = 0
  • x = 8

The solutions are x = 8, and x = -8.

User Berming
by
7.8k points

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