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f\left(n\right)=\left\{\frac{\frac{n}{2}\ \ \ \ if\ n\ is\ even}{3n+1\ \ \ \ \ \ if\ n\ is\ odd}\right\}

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Answer: N → N/2 ( if N is even) N → 3N + 1 (if N is odd) i.e. If N is even, divide it by 2 to get N/2. If N is odd, multiply it by 3 and add 1 to obtain 3N + 1. It is conjectured but not yet proven that no matter which positive integer we start with; we always end up with 1

User YellowWebMonkey
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Answer:

what is this meant to mean¯\_ಠ_ಠ_/¯

User Waclock
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