224k views
4 votes
In Case 1, a force F is pushing perpendicular on an object a distance L/2 from the rotation axis. In Case 2 the same force is pushing at an angle of 30 degrees a distance L from the axis.1)In which case is the torque due to the force about the rotation axis biggest?

a. Case 1b. Case 2c. Same

1 Answer

2 votes

Step-by-step explanation:

Case 1,

A force F is pushing perpendicular on an object a distance L/2 from the rotation axis. Torque is given by :


\tau_1=Fd\sin \theta\\\\\tau_1=(FL)/(2)\sin (90)\\\\\tau_1=(FL)/(2)\ ..........(1)

Case 2,

The same force is pushing at an angle of 30 degrees a distance L from the axis. New torque is given by :


\tau_2=Fd\sin \theta\\\\\tau_2=FL\sin (30)\\\\\tau_2=(FL)/(2)\ ..........(2)

From equation (1) and (2), it is clear that the force in both cases is same.

User Sancho
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.