Step-by-step explanation:
Case 1,
A force F is pushing perpendicular on an object a distance L/2 from the rotation axis. Torque is given by :
![\tau_1=Fd\sin \theta\\\\\tau_1=(FL)/(2)\sin (90)\\\\\tau_1=(FL)/(2)\ ..........(1)](https://img.qammunity.org/2021/formulas/physics/college/ddpoezhnlsav356vn8dx81u85stbcfqkwf.png)
Case 2,
The same force is pushing at an angle of 30 degrees a distance L from the axis. New torque is given by :
![\tau_2=Fd\sin \theta\\\\\tau_2=FL\sin (30)\\\\\tau_2=(FL)/(2)\ ..........(2)](https://img.qammunity.org/2021/formulas/physics/college/dby5twksjdunc666zroiwu6gw41zf4yd52.png)
From equation (1) and (2), it is clear that the force in both cases is same.