Answer:
A) 150 kW will be required to heat the building using electrical-resistance heating, this is because, electrical-resistance heating is 100% efficient.
B) for a heat pump whose coefficient of performance is 4,
Using COP = Q/W
where,
Q = heat delivered
W = power or work input.
4 = 150/W,
W = 150/4 = 37.5 kW
C) COP for reversible heat pump is given as
COP = T2/(T2-T1)
Where T2 = hot temperature = 20 + 273 = 293 K
T1 = cold temperatures = 10 + 273 = 283 K
COP = 293/(293-283) = 29.3
COP = Q/W
29.3 =150/W
W = 0.195 kW = 195.3 watts