Question

What would be the normal weight of a chair if the coefficient of friction between it and the floor is 0.38 and the force needed to push it is 88 lbs.?

Answer 1

Explanation:

μ = 0.38

F = 88lbs

N = ?

The force acting on a surface F =

F = μN

Where F = force acting on the body

N = Normal force

μ = coefficient of static friction

N = F / μ

N = 88 / 0.38

N = 231.578N

N = 231.6N

The normal force acting on the body is 231.6N