Answer:
A) 2.19*10^{-7} T
B) 4.27*10^{-8} J/m^3
C) 12.82 W/m^2
Step-by-step explanation:
The relation between magnetic and electric field is given by:

A) Hence, the magnitude of the magnetic field is:

B) the energy density is:

C) the flow per unit area can be computed with the magnitude of the Poynting vector:

hope this helps!!