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At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 69.5 V/m. Find the magnetic field strength B, the total energy density u, and the power flow per unit area, all at the same instant and location.

Magnetic Field=__________ T -Energy density=__________ J/m^3 -Power flow per unit are=________ W/m^2

1 Answer

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Answer:

A) 2.19*10^{-7} T

B) 4.27*10^{-8} J/m^3

C) 12.82 W/m^2

Step-by-step explanation:

The relation between magnetic and electric field is given by:


c=(E)/(B)

A) Hence, the magnitude of the magnetic field is:


B=(E)/(c)=(65.9(V)/(m))/(3*10^(8)(m)/(s))=2.19*10^(-7)T

B) the energy density is:


u_E=(1)/(2)\epsilon_0 E^2=(1)/(2)(8.85*10^(-12)(C^2)/(Nm^2))(69.5(V)/(m))^2=4.27*10^(-8)(J)/(m^3)

C) the flow per unit area can be computed with the magnitude of the Poynting vector:


S=c\epsilon_0|E|^2=(3*10^8(m)/(s))(8.85*10^(-12)(C^2)/(Nm^2))|69.5(V)/(m)|^2=12.82(W)/(m^2)

hope this helps!!

User AronVanAmmers
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