Question

a compact disc has an approximate radius of 2 3/8 inches. disregarding the small hole at the center of the CD, what is the approximate area of a CD?

Answer 1

The area of CD is 17.71
`in^(2)`

Explanation:

Radius of the disk =
`2(3)/(8)` = 2.375 in

Since CD is in shape of circle So area of the circle is given by

`A = \pi r^(2)`

Put the value of radius in above equation we get

A = 3.14 ×
`2.375^(2)`

A = 17.71
`in^(2)`

Therefore the area of CD is 17.71
`in^(2)`