Answer:
The speed is 2.427 x10⁸ m/s
Step-by-step explanation:
The equation for measured time is the following:
![t'=xt_(o)](https://img.qammunity.org/2021/formulas/physics/college/1mgyhjfqrk54d3hfaqdb3bkk4jgu5ahiw5.png)
Where
x = 0.587
Replacing:
![t'=0.587t_(o)](https://img.qammunity.org/2021/formulas/physics/college/9vz6bunsxublk7jpkix76wnfemom73jk0v.png)
The equation for the speed is:
![t'=\frac{t_(o) }{\sqrt{1-((v^(2) )/(c^(2) )) } } \\0.587t_(o) =\frac{t_(o) }{\sqrt{1-((v^(2) )/(c^(2) )) } }\\0.587=\sqrt{1-(v^(2) )/(c^(2) ) } \\0.587^(2) =1-(v^(2) )/(c^(2) )](https://img.qammunity.org/2021/formulas/physics/college/agfajn6rqdxryskqkxz04oj649dayfnkbh.png)
Rearrange the expression:
![0.344=1-(x^(2) )/(c^(2) ) \\v=\sqrt{0.656c^(2) } =0.809c](https://img.qammunity.org/2021/formulas/physics/college/x7topooxkgsj0wjnayvr8drgud5yipptli.png)
Where c = 3x10⁸m/s
Replacing:
v = 0.809 * 3x10⁸ = 2.427 x10⁸ m/s