Question

Calculate the reliability of a hard disk drive with an MTBF of 4,622 hours during the crucial last 16 hours of the last fiscal quarter—the three-month period beginning on October 1 and ending on December 31. Assume e 5 2.71828, and use the reliability formula from the previous exercise.

Answer 1

2.714

Step-by-step explanation:

With MTBF of 4622 hours during the last 16 hours, reliability is according to the formula:

Reliability (t)=e-(1/MTBF)

(t)=e-(16/4622)

=e-0.0034617

=2718-0.0034617

=2.714

Answer 2

R(16) = 99.7%

Step-by-step explanation:

Mean Time Before Failure, MTBF = 4622 hours

The reliability is to be calculated for the last 16 hours, t =16 hrs

The relationship between the reliability and MTBF is given by:

`R(t) = e^{(-t)/(MTBF) }`

`R(16) = e^{(-16)/(4622) }`

R(16) = 0.997

R(16) = 99.7%