Question

Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of hydrochloric acid (HCl) is mixed with an aqueous solution of potassium hydroxide (KOH). Indicate the physical states of the reactants and products using the abbreviations (s), (l), (g), or (aq) for solids, liquids, gases, or aqueous solutions, respectively.

Answer 1

See explanation below

Step-by-step explanation:

We have a acid base reaction of HCl and KOH, both of them are in aqueous solution. Now to get the product, we need to write the reaction first:

HCl + KOH ------->

This is an acid base reaction, and when they react it forms different products.A reaction of this type it's usually a double displacement reaction. Now, How do you know it can be a double displacement?, the key is the state of the reactants. Both of them are in aqueous solution, which means that both of them are dissolved in water respectively. In water, each of these reactants can be dissociated like this, like a decomposition reaction:

For the acid:

HCl -----> H⁺ + Cl⁻

For the base:

KOH -------> K⁺ + OH⁻

So, when the reaction occurs, both reactants dissociate first into these ions. Then, they all regroup with different ions. In the case of the H⁺, it will go to the OH⁻ (Opposites attract) and the K⁺ will go to the Cl⁻.

When this happens, the reaction gets neutralized and forms the following products:

HCl + KOH --------> KCl + H₂O

Now, let's see the states of the products. In the case of KCl, is a neutralization reaction, and we have a metal with a nonmetal reacting, and when the acid and base react, the KCl will formed as a precipitate, so, this will be solid. In the case of water, this would be in liquid state. So the final reaction would be:

HCl(aq) + KOH(aq) --------> KCl(s) + H₂O(l)

Answer 2

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

Step-by-step explanation:

Aqueous solution of HCl and aqueous solution of KOH react as follow:

HCl(aq) + KOH(aq) —>

In solution, HCl and KOH will dissociates as follow:

HCl —> H+ + Cl-

KOH —> K+ + OH-

During the reaction, a double displacement reaction occur as shown below:

H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-

The elemental equation is given below:

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)