Answer:
The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? Round to the nearest hundredth.
The equation that represents the problem is 48 = 96t - 16t2.
Solve 16t2 - 96t + 48 = 0.
Complete the square to write 16t² - 96t + 48 = 0 as
(t - 3)² = 6
Solve (t - 3)² = 6. The arrow is at a height of 48 ft after approximately
0.55
and after
5.45
Explanation:
just did it on edge