Question

The height of an arrow shot upward can be given by the formula s = vnt - 16, where vo is the initial

velocity and t is time. How long does it take for the arrow to reach a height of 48 ft if it has an initial
velocity of 96 ft/s? Round to the nearest hundredth.
The equation that represents the problem is 48 = 96t - 1612.
Solve 16t - 960 +48 = 0.
Complete the square to write 161-961 +48 = 0 as

Answer 1

The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? Round to the nearest hundredth.

The equation that represents the problem is 48 = 96t - 16t2.

Solve 16t2 - 96t + 48 = 0.

Complete the square to write 16t² - 96t + 48 = 0 as

(t - 3)² = 6

Solve (t - 3)² = 6. The arrow is at a height of 48 ft after approximately

0.55

and after

5.45

Explanation:

just did it on edge

Answer 2

the answer is (t - 3)² = 6

the next questions are 0.55 and 5.45

Explanation:

just did it on edge