Answer:
0.192 g of ice will melt.
Step-by-step explanation:
Applying the law of conservation of energy to the given situation, we get:
Heat Energy lost by Bullet + Kinetic Energy of Bullet = Heat Gained by Ice
m₁CΔT + (1/2)m₁v² = m₂L
where,
m₁ = mass of bullet = 2.55 g = 2.55 x 10⁻³ kg
C = specific heat of lead = 128 J/kg
ΔT = Difference in temperature of bullet and ice = 21.2°C
v = speed of bullet = 212 m/s
L = latent heat of fusion o water = 3.33 x 10⁵ J/kg °C
Therefore,
(2.55 x 10⁻³ kg)(128 J/kg °C)(21.2°C) + (1/2)(2.55 x 10⁻³ kg)(212 m/s)² = m₂(3.33 x 10⁵ J/kg)
m₂ = 64.22 J/3.33 x 10⁵ J/kg
m₂ = 1.92 x 10⁻⁴ kg = 0.192 g