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How many grams of oxygen are needed to react with 4.6 grams of titanium (IV) chloride

1 Answer

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Answer:

1.24g

Step-by-step explanation:

Given parameters:

Mass of titanium (IV) chloride = 4.6g

Unknown:

Mass of oxygen = ?

Solution:

To solve this problem, we need to write the balance reaction equation first;

TiCl₂ + O₂ → TiO₂ + Cl₂

Now to find the mass of the oxygen gas,

Express the given mass of the known TiCl₂ in moles:

Number of moles of TiCl₂ =
(mass)/(molar mass)

Molar mass of TiC₂ = 47.9 + 2(35.5) = 118.9g/mol

Number of moles of TiCl₂ =
(4.6)/(118.9) = 0.04mole

From the reaction equation;

1 mole of TiCl₂ reacted with 1 mole of oxygen gas

0.04 mole of TiCl₂ will react with 0.04 mole of oxygen gas

Mass of oxygen gas = number of moles x molar mass

molar mass of oxygen gas = 2(16) = 32g/mol

Mass of oxygen gas = 0.04 x 32 = 1.24g

User Michael Blackburn
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