Question

A GAS SAMPLE HAS A TEMPERATURE OF 18 CELSIUS WITH AN UNKNOWN VOLUME. THE SAME GAS HAS A VOLUME OF 436 ML WHEN THE TEMPERATURE IS 91 CELSIUS WITH NO CHANGE IN THE PRESSURE AND AMOUNT OF GAS

Answer 1

Answer : The unknown volume will be, 348.6 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1\text{ and }T_1` are the initial volume and temperature of the gas.

`V_2\text{ and }T_2` are the final volume and temperature of the gas.

We are given:

`V_1=?\\T_1=18^oC=(18+273)K=291K\\V_2=436mL\\T_2=91^oC=(91+273)K=364K`

Now put all the given values in above equation, we get:

`(V_1)/(291K)=(436mL)/(364K)\\\\V_1=348.6mL`

Therefore, the unknown volume will be, 348.6 mL