Answer:
Static friction coefficient, μ = 0.41796
Step-by-step explanation:
radius, r = 2.5 m
constant acceleration, a = 0.32 m/s²
time, t = 10 s
∴ Tangential Velocity, V = at
⇒ 0.32 × 10 ⇒ 3.2 m/s
now,
radial acceleration = V² / r
⇒ (3.2)² / 2.5 ⇒ 4.096 ms⁻²
Force required = m × radial acceleration
μmg = m × [(3.2)² / 2.5]
'm' cancels each other on both sides
μg = (3.2)² / 2.5
multiply through by 'g' to make coefficient of static friction the subject
where g = 9.8
μ = (3.2)² / 9.8 × 2.5
μ = 10.24 / 24.5
μ = 0.41796