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A heavy ball with a weight of 150 N is hung from the ceiling of a lecture hall on a 4.1-m-long rope. The ball is pulled to one side and released to swing as a pendulum, reaching a speed of 5.5 m/s as it passes through the lowest point. What is the tension in the rope at that point?

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Answer:

The tension in the rope is 262.88 N

Step-by-step explanation:

Given:

Weight
W = 150 N

Length of rope
r = 4.1 m

Initial speed of ball
v = 5.5 (m)/(s)

For finding the tension in the rope,

First find the mass of rod,


mg = 150 (
g = 9.8 (m)/(s^(2) ) )


m = (150)/(9.8)


m = 15.3 kg

Tension in the rope is,


T = mg + (mv^(2) )/(r)


T = 150 + (15.3 * (5.5)^(2) )/(4.1)


T = 262.88 N

Therefore, the tension in the rope is 262.88 N

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